(x-5)(x+2)=(x-3)(x-1)

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Solution for (x-5)(x+2)=(x-3)(x-1) equation: 



(x-5)(x+2)=(x-3)(x-1)

We move all terms to the left:

(x-5)(x+2)-((x-3)(x-1))=0

We multiply parentheses ..

(+x^2+2x-5x-10)-((x-3)(x-1))=0



We calculate terms in parentheses: -((x-3)(x-1)), so:

(x-3)(x-1)

We multiply parentheses ..

(+x^2-1x-3x+3)

We get rid of parentheses

x^2-1x-3x+3

We add all the numbers together, and all the variables

x^2-4x+3

Back to the equation:

-(x^2-4x+3)



We get rid of parentheses

x^2-x^2+2x-5x+4x-10-3=0

We add all the numbers together, and all the variables

x-13=0

We move all terms containing x to the left, all other terms to the right

x=13

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