(x-5)(x+3)=(x+7)(x+4)

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Solution for (x-5)(x+3)=(x+7)(x+4) equation: 



(x-5)(x+3)=(x+7)(x+4)

We move all terms to the left:

(x-5)(x+3)-((x+7)(x+4))=0

We multiply parentheses ..

(+x^2+3x-5x-15)-((x+7)(x+4))=0



We calculate terms in parentheses: -((x+7)(x+4)), so:

(x+7)(x+4)

We multiply parentheses ..

(+x^2+4x+7x+28)

We get rid of parentheses

x^2+4x+7x+28

We add all the numbers together, and all the variables

x^2+11x+28

Back to the equation:

-(x^2+11x+28)



We get rid of parentheses

x^2-x^2+3x-5x-11x-15-28=0

We add all the numbers together, and all the variables

-13x-43=0

We move all terms containing x to the left, all other terms to the right

-13x=43

x=43/-13

x=-3+4/13

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