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(x-5)(x+3)=(x-7)(x
We move all terms to the left:
(x-5)(x+3)-((x-7)(x)=0
We multiply parentheses ..
(+x^2+3x-5x-15)-((x-7)x=0
We get rid of parentheses
x^2+3x-5x-((x-7)x-15=0
We add all the numbers together, and all the variables
x^2-2x-((x-7)x-15=0
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