(x-5)(x+3)=(x-7)(x

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Solution for (x-5)(x+3)=(x-7)(x equation: 



(x-5)(x+3)=(x-7)(x

We move all terms to the left:

(x-5)(x+3)-((x-7)(x)=0

We multiply parentheses ..

(+x^2+3x-5x-15)-((x-7)x=0

We get rid of parentheses

x^2+3x-5x-((x-7)x-15=0

We add all the numbers together, and all the variables

x^2-2x-((x-7)x-15=0

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