(x-5)(x+4)=(x+7)(x-3)

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Solution for (x-5)(x+4)=(x+7)(x-3) equation: 



(x-5)(x+4)=(x+7)(x-3)

We move all terms to the left:

(x-5)(x+4)-((x+7)(x-3))=0

We multiply parentheses ..

(+x^2+4x-5x-20)-((x+7)(x-3))=0



We calculate terms in parentheses: -((x+7)(x-3)), so:

(x+7)(x-3)

We multiply parentheses ..

(+x^2-3x+7x-21)

We get rid of parentheses

x^2-3x+7x-21

We add all the numbers together, and all the variables

x^2+4x-21

Back to the equation:

-(x^2+4x-21)



We get rid of parentheses

x^2-x^2+4x-5x-4x-20+21=0

We add all the numbers together, and all the variables

-5x+1=0

We move all terms containing x to the left, all other terms to the right

-5x=-1

x=-1/-5

x=1/5

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