(x-5)(x+5)-(x+1)(x+2)=0

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Solution for (x-5)(x+5)-(x+1)(x+2)=0 equation:



(x-5)(x+5)-(x+1)(x+2)=0
We use the square of the difference formula
x^2-(x+1)(x+2)-25=0
We multiply parentheses ..
x^2-(+x^2+2x+x+2)-25=0
We get rid of parentheses
x^2-x^2-2x-x-2-25=0
We add all the numbers together, and all the variables
-3x-27=0
We move all terms containing x to the left, all other terms to the right
-3x=27
x=27/-3
x=-9

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