(x-5)(x+8)=(x-2)(x+1)6

Solution for (x-5)(x+8)=(x-2)(x+1)6 equation:

(x-5)(x+8)=(x-2)(x+1)6

We move all terms to the left:

(x-5)(x+8)-((x-2)(x+1)6)=0

We multiply parentheses ..

(+x^2+8x-5x-40)-((x-2)(x+1)6)=0


We calculate terms in parentheses: -((x-2)(x+1)6), so:

(x-2)(x+1)6

We multiply parentheses ..

(+x^2+x-2x-2)6

We multiply parentheses

6x^2+6x-12x-12

We add all the numbers together, and all the variables

6x^2-6x-12

Back to the equation:

-(6x^2-6x-12)


We get rid of parentheses

x^2-6x^2+8x-5x+6x-40+12=0

We add all the numbers together, and all the variables

-5x^2+9x-28=0

a = -5; b = 9; c = -28;
Δ = b2-4ac
Δ = 92-4·(-5)·(-28)
Δ = -479
Delta is less than zero, so there is no solution for the equation