(x-5)(x-1)=(x+2)(x-3)

Solution for (x-5)(x-1)=(x+2)(x-3) equation:

(x-5)(x-1)=(x+2)(x-3)

We move all terms to the left:

(x-5)(x-1)-((x+2)(x-3))=0

We multiply parentheses ..

(+x^2-1x-5x+5)-((x+2)(x-3))=0


We calculate terms in parentheses: -((x+2)(x-3)), so:

(x+2)(x-3)

We multiply parentheses ..

(+x^2-3x+2x-6)

We get rid of parentheses

x^2-3x+2x-6

We add all the numbers together, and all the variables

x^2-1x-6

Back to the equation:

-(x^2-1x-6)


We get rid of parentheses

x^2-x^2-1x-5x+1x+5+6=0

We add all the numbers together, and all the variables

-5x+11=0

We move all terms containing x to the left, all other terms to the right

-5x=-11

x=-11/-5

x=2+1/5