(x-5)(x-3)=-1

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Solution for (x-5)(x-3)=-1 equation: 



(x-5)(x-3)=-1

We move all terms to the left:

(x-5)(x-3)-(-1)=0

We add all the numbers together, and all the variables

(x-5)(x-3)+1=0

We multiply parentheses ..

(+x^2-3x-5x+15)+1=0

We get rid of parentheses

x^2-3x-5x+15+1=0

We add all the numbers together, and all the variables

x^2-8x+16=0

a = 1; b = -8; c = +16;
Δ = b2-4ac
Δ = -82-4·1·16
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{8}{2}=4$

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