(x-5)(x-4)=-20

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Solution for (x-5)(x-4)=-20 equation: 



(x-5)(x-4)=-20

We move all terms to the left:

(x-5)(x-4)-(-20)=0

We add all the numbers together, and all the variables

(x-5)(x-4)+20=0

We multiply parentheses ..

(+x^2-4x-5x+20)+20=0

We get rid of parentheses

x^2-4x-5x+20+20=0

We add all the numbers together, and all the variables

x^2-9x+40=0

a = 1; b = -9; c = +40;
Δ = b2-4ac
Δ = -92-4·1·40
Δ = -79
Delta is less than zero, so there is no solution for the equation

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