(x-5)(x-5)-(x+4)(x+4)=9x

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Solution for (x-5)(x-5)-(x+4)(x+4)=9x equation: 



(x-5)(x-5)-(x+4)(x+4)=9x

We move all terms to the left:

(x-5)(x-5)-(x+4)(x+4)-(9x)=0

We add all the numbers together, and all the variables

-9x+(x-5)(x-5)-(x+4)(x+4)=0

We multiply parentheses ..

(+x^2-5x-5x+25)-9x-(x+4)(x+4)=0

We get rid of parentheses

x^2-5x-5x-9x-(x+4)(x+4)+25=0

We multiply parentheses ..

x^2-(+x^2+4x+4x+16)-5x-5x-9x+25=0

We add all the numbers together, and all the variables

x^2-(+x^2+4x+4x+16)-19x+25=0

We get rid of parentheses

x^2-x^2-4x-4x-19x-16+25=0

We add all the numbers together, and all the variables

-27x+9=0

We move all terms containing x to the left, all other terms to the right

-27x=-9

x=-9/-27

x=1/3

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