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(x-5)(x-5)-(x-4)(x-10)=35
We move all terms to the left:
(x-5)(x-5)-(x-4)(x-10)-(35)=0
We multiply parentheses ..
(+x^2-5x-5x+25)-(x-4)(x-10)-35=0
We get rid of parentheses
x^2-5x-5x-(x-4)(x-10)+25-35=0
We multiply parentheses ..
x^2-(+x^2-10x-4x+40)-5x-5x+25-35=0
We add all the numbers together, and all the variables
x^2-(+x^2-10x-4x+40)-10x-10=0
We get rid of parentheses
x^2-x^2+10x+4x-10x-40-10=0
We add all the numbers together, and all the variables
4x-50=0
We move all terms containing x to the left, all other terms to the right
4x=50
x=50/4
x=12+1/2
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