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(x-5)(x-5)-121=0

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Solution for (x-5)(x-5)-121=0 equation:



(x-5)(x-5)-121=0
We multiply parentheses ..
(+x^2-5x-5x+25)-121=0
We get rid of parentheses
x^2-5x-5x+25-121=0
We add all the numbers together, and all the variables
x^2-10x-96=0
a = 1; b = -10; c = -96;
Δ = b2-4ac
Δ = -102-4·1·(-96)
Δ = 484
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
x_{1}=\frac{-b-\sqrt{\Delta}}{2a}
x_{2}=\frac{-b+\sqrt{\Delta}}{2a}

\sqrt{\Delta}=\sqrt{484}=22
x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-10)-22}{2*1}=\frac{-12}{2} =-6
x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-10)+22}{2*1}=\frac{32}{2} =16

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