(x-5)(x-5)=-2+2x

Solution for (x-5)(x-5)=-2+2x equation:

(x-5)(x-5)=-2+2x

We move all terms to the left:

(x-5)(x-5)-(-2+2x)=0

We add all the numbers together, and all the variables

(x-5)(x-5)-(2x-2)=0

We get rid of parentheses

(x-5)(x-5)-2x+2=0

We multiply parentheses ..

(+x^2-5x-5x+25)-2x+2=0

We get rid of parentheses

x^2-5x-5x-2x+25+2=0

We add all the numbers together, and all the variables

x^2-12x+27=0

a = 1; b = -12; c = +27;
Δ = b2-4ac
Δ = -122-4·1·27
Δ = 36
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{36}=6$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-12)-6}{2*1}=\frac{6}{2}
=3
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-12)+6}{2*1}=\frac{18}{2}
=9
$