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(x-5)(x-6)=120
We move all terms to the left:
(x-5)(x-6)-(120)=0
We multiply parentheses ..
(+x^2-6x-5x+30)-120=0
We get rid of parentheses
x^2-6x-5x+30-120=0
We add all the numbers together, and all the variables
x^2-11x-90=0
a = 1; b = -11; c = -90;
Δ = b2-4ac
Δ = -112-4·1·(-90)
Δ = 481
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-11)-\sqrt{481}}{2*1}=\frac{11-\sqrt{481}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-11)+\sqrt{481}}{2*1}=\frac{11+\sqrt{481}}{2} $
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