(x-5)+(x-4)(4-x)=0

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Solution for (x-5)+(x-4)(4-x)=0 equation: 



(x-5)+(x-4)(4-x)=0

We add all the numbers together, and all the variables

(x-5)+(x-4)(-1x+4)=0

We get rid of parentheses

x+(x-4)(-1x+4)-5=0

We multiply parentheses ..

(-1x^2+4x+4x-16)+x-5=0

We get rid of parentheses

-1x^2+4x+4x+x-16-5=0

We add all the numbers together, and all the variables

-1x^2+9x-21=0

a = -1; b = 9; c = -21;
Δ = b2-4ac
Δ = 92-4·(-1)·(-21)
Δ = -3
Delta is less than zero, so there is no solution for the equation

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