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(x-5)+(x-5)=(x-5)+(x-5)
We move all terms to the left:
(x-5)+(x-5)-((x-5)+(x-5))=0
We get rid of parentheses
x+x-((x-5)+(x-5))-5-5=0
We calculate terms in parentheses: -((x-5)+(x-5)), so:We add all the numbers together, and all the variables
(x-5)+(x-5)
We get rid of parentheses
x+x-5-5
We add all the numbers together, and all the variables
2x-10
Back to the equation:
-(2x-10)
2x-(2x-10)-10=0
We get rid of parentheses
2x-2x+10-10=0
We add all the numbers together, and all the variables
=0
x=0/1
x=0
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