(x-5)/(3*x)+(6/2*x+1)=0

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Solution for (x-5)/(3*x)+(6/2*x+1)=0 equation: 


D( x )

3*x = 0

3*x = 0

3*x = 0

3*x = 0 // : 3

x = 0

x in (-oo:0) U (0:+oo)

(x-5)/(3*x)+(6/2)*x+1 = 0

(x-5)/(3*x)+3*x+1 = 0

(x-5)/(3*x)+((3*x)^2)/(3*x)+(1*3*x)/(3*x) = 0

9*x^2+x+1*3*x-5 = 0

9*x^2+x+3*x-5 = 0

9*x^2+4*x-5 = 0

9*x^2+4*x-5 = 0

9*x^2+4*x-5 = 0

DELTA = 4^2-(-5*4*9)

DELTA = 196

DELTA > 0

x = (196^(1/2)-4)/(2*9) or x = (-196^(1/2)-4)/(2*9)

x = 5/9 or x = -1

(x+1)*(x-5/9) = 0

((x+1)*(x-5/9))/(3*x) = 0

((x+1)*(x-5/9))/(3*x) = 0 // * 3*x

(x+1)*(x-5/9) = 0

( x+1 )

x+1 = 0 // - 1

x = -1

( x-5/9 )

x-5/9 = 0 // + 5/9

x = 5/9

x in { -1, 5/9 }

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