(x-5)/(30-2x)=10

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Solution for (x-5)/(30-2x)=10 equation: 



(x-5)/(30-2x)=10

We move all terms to the left:

(x-5)/(30-2x)-(10)=0



Domain of the equation: (30-2x)!=0

We move all terms containing x to the left, all other terms to the right

-2x!=-30

x!=-30/-2

x!=+15

x∈R



We add all the numbers together, and all the variables

(x-5)/(-2x+30)-10=0

We multiply all the terms by the denominator


(x-5)-10*(-2x+30)=0

We multiply parentheses

(x-5)+20x-300=0

We get rid of parentheses

x+20x-5-300=0

We add all the numbers together, and all the variables

21x-305=0

We move all terms containing x to the left, all other terms to the right

21x=305

x=305/21

x=14+11/21

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