(x-5)/(7x-35)

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Solution for (x-5)/(7x-35) equation: 


D( x )

7*x-35 = 0

7*x-35 = 0

7*x-35 = 0

7*x-35 = 0 // + 35

7*x = 35 // : 7

x = 35/7

x = 5

x in (-oo:5) U (5:+oo)

(x-5)/(7*x-35) = 0

x-5 = 0 // + 5

x = 5

x in { 5} 

x belongs to the empty set

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