(x-5)/3+(5)/3=(-x)/7

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Solution for (x-5)/3+(5)/3=(-x)/7 equation:



(x-5)/3+(5)/3=(-x)/7
We move all terms to the left:
(x-5)/3+(5)/3-((-x)/7)=0
We add all the numbers together, and all the variables
(x-5)/3-((-1x)/7)+5/3=0
We calculate fractions
(x-5)/()+(-((-1x)*3)/()=0
We calculate terms in parentheses: +(-((-1x)*3)/(), so:
-((-1x)*3)/(
We multiply all the terms by the denominator
-((-1x)*3)
We calculate terms in parentheses: -((-1x)*3), so:
(-1x)*3
We multiply parentheses
-3x
Back to the equation:
-(-3x)
We get rid of parentheses
3x
Back to the equation:
+(3x)
We add all the numbers together, and all the variables
3x+(x-5)/()=0
We multiply all the terms by the denominator
3x*()+(x-5)=0
We get rid of parentheses
3x*()+x-5=0
We add all the numbers together, and all the variables
x+3x*()-5=0
We move all terms containing x to the left, all other terms to the right
x+3x*()=5

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