(x-5)/3+(5)/3=(-x)/7

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Solution for (x-5)/3+(5)/3=(-x)/7 equation: 



(x-5)/3+(5)/3=(-x)/7

We move all terms to the left:

(x-5)/3+(5)/3-((-x)/7)=0

We add all the numbers together, and all the variables

(x-5)/3-((-1x)/7)+5/3=0

We calculate fractions


(x-5)/()+(-((-1x)*3)/()=0



We calculate terms in parentheses: +(-((-1x)*3)/(), so:

-((-1x)*3)/(

We multiply all the terms by the denominator


-((-1x)*3)



We calculate terms in parentheses: -((-1x)*3), so:

(-1x)*3

We multiply parentheses

-3x

Back to the equation:

-(-3x)



We get rid of parentheses

3x

Back to the equation:

+(3x)



We add all the numbers together, and all the variables

3x+(x-5)/()=0

We multiply all the terms by the denominator


3x*()+(x-5)=0

We get rid of parentheses

3x*()+x-5=0

We add all the numbers together, and all the variables

x+3x*()-5=0

We move all terms containing x to the left, all other terms to the right

x+3x*()=5

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