(x-5)/3-(x-2)/9=(3x-3)/9

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Solution for (x-5)/3-(x-2)/9=(3x-3)/9 equation:



(x-5)/3-(x-2)/9=(3x-3)/9
We move all terms to the left:
(x-5)/3-(x-2)/9-((3x-3)/9)=0
We calculate fractions
x/()+(-3x+6)/()+(-((3x-3)*3)/()=0
We calculate terms in parentheses: +(-((3x-3)*3)/(), so:
-((3x-3)*3)/(
We multiply all the terms by the denominator
-((3x-3)*3)
We calculate terms in parentheses: -((3x-3)*3), so:
(3x-3)*3
We multiply parentheses
9x-9
Back to the equation:
-(9x-9)
We get rid of parentheses
-9x+9
Back to the equation:
+(-9x+9)
We get rid of parentheses
x/()+(-3x+6)/()-9x+9=0
We multiply all the terms by the denominator
x+(-3x+6)-9x*()+9*()=0
We add all the numbers together, and all the variables
x+(-3x+6)-9x*()=0
We get rid of parentheses
x-3x-9x*()+6=0
We add all the numbers together, and all the variables
-2x-9x*()+6=0
We move all terms containing x to the left, all other terms to the right
-2x-9x*()=-6

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