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(x-5)/3=(3x+1)/7
We move all terms to the left:
(x-5)/3-((3x+1)/7)=0
We calculate fractions
x/()+(-((3x+1)*3)/()=0
We calculate terms in parentheses: +(-((3x+1)*3)/(), so:We get rid of parentheses
-((3x+1)*3)/(
We multiply all the terms by the denominator
-((3x+1)*3)
We calculate terms in parentheses: -((3x+1)*3), so:We get rid of parentheses
(3x+1)*3
We multiply parentheses
9x+3
Back to the equation:
-(9x+3)
-9x-3
Back to the equation:
+(-9x-3)
x/()-9x-3=0
We multiply all the terms by the denominator
x-9x*()-3*()=0
We add all the numbers together, and all the variables
x-9x*()=0
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