(x-5)=3(x+2)-x-16

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Solution for (x-5)=3(x+2)-x-16 equation: 



(x-5)=3(x+2)-x-16

We move all terms to the left:

(x-5)-(3(x+2)-x-16)=0

We get rid of parentheses

x-(3(x+2)-x-16)-5=0



We calculate terms in parentheses: -(3(x+2)-x-16), so:

3(x+2)-x-16

We add all the numbers together, and all the variables

-1x+3(x+2)-16

We multiply parentheses

-1x+3x+6-16

We add all the numbers together, and all the variables

2x-10

Back to the equation:

-(2x-10)



We get rid of parentheses

x-2x+10-5=0

We add all the numbers together, and all the variables

-1x+5=0

We move all terms containing x to the left, all other terms to the right

-x=-5

x=-5/-1

x=+5

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