(x-6)(2x-14)=0

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Solution for (x-6)(2x-14)=0 equation:



(x-6)(2x-14)=0
We multiply parentheses ..
(+2x^2-14x-12x+84)=0
We get rid of parentheses
2x^2-14x-12x+84=0
We add all the numbers together, and all the variables
2x^2-26x+84=0
a = 2; b = -26; c = +84;
Δ = b2-4ac
Δ = -262-4·2·84
Δ = 4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{4}=2$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-26)-2}{2*2}=\frac{24}{4} =6 $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-26)+2}{2*2}=\frac{28}{4} =7 $

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