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(x-6)(2x-14)=0
We multiply parentheses ..
(+2x^2-14x-12x+84)=0
We get rid of parentheses
2x^2-14x-12x+84=0
We add all the numbers together, and all the variables
2x^2-26x+84=0
a = 2; b = -26; c = +84;
Δ = b2-4ac
Δ = -262-4·2·84
Δ = 4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{4}=2$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-26)-2}{2*2}=\frac{24}{4} =6 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-26)+2}{2*2}=\frac{28}{4} =7 $
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