(x-6)(2x-3)=(x+7)(2x+3)

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Solution for (x-6)(2x-3)=(x+7)(2x+3) equation:



(x-6)(2x-3)=(x+7)(2x+3)
We move all terms to the left:
(x-6)(2x-3)-((x+7)(2x+3))=0
We multiply parentheses ..
(+2x^2-3x-12x+18)-((x+7)(2x+3))=0
We calculate terms in parentheses: -((x+7)(2x+3)), so:
(x+7)(2x+3)
We multiply parentheses ..
(+2x^2+3x+14x+21)
We get rid of parentheses
2x^2+3x+14x+21
We add all the numbers together, and all the variables
2x^2+17x+21
Back to the equation:
-(2x^2+17x+21)
We get rid of parentheses
2x^2-2x^2-3x-12x-17x+18-21=0
We add all the numbers together, and all the variables
-32x-3=0
We move all terms containing x to the left, all other terms to the right
-32x=3
x=3/-32
x=-3/32

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