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(x-6)(2x-6)=20x
We move all terms to the left:
(x-6)(2x-6)-(20x)=0
We add all the numbers together, and all the variables
-20x+(x-6)(2x-6)=0
We multiply parentheses ..
(+2x^2-6x-12x+36)-20x=0
We get rid of parentheses
2x^2-6x-12x-20x+36=0
We add all the numbers together, and all the variables
2x^2-38x+36=0
a = 2; b = -38; c = +36;
Δ = b2-4ac
Δ = -382-4·2·36
Δ = 1156
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1156}=34$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-38)-34}{2*2}=\frac{4}{4} =1 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-38)+34}{2*2}=\frac{72}{4} =18 $
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