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(x-6)(540/x-6)=540
We move all terms to the left:
(x-6)(540/x-6)-(540)=0
Domain of the equation: x-6)!=0We multiply parentheses ..
x∈R
(+540x^2-6x-3240x+36)-540=0
We get rid of parentheses
540x^2-6x-3240x+36-540=0
We add all the numbers together, and all the variables
540x^2-3246x-504=0
a = 540; b = -3246; c = -504;
Δ = b2-4ac
Δ = -32462-4·540·(-504)
Δ = 11625156
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{11625156}=\sqrt{36*322921}=\sqrt{36}*\sqrt{322921}=6\sqrt{322921}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-3246)-6\sqrt{322921}}{2*540}=\frac{3246-6\sqrt{322921}}{1080} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-3246)+6\sqrt{322921}}{2*540}=\frac{3246+6\sqrt{322921}}{1080} $
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