(x-6)(7-x)=10-x2

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Solution for (x-6)(7-x)=10-x2 equation: 



(x-6)(7-x)=10-x2

We move all terms to the left:

(x-6)(7-x)-(10-x2)=0

We add all the numbers together, and all the variables

-(-1x^2+10)+(x-6)(-1x+7)=0

We get rid of parentheses

1x^2+(x-6)(-1x+7)-10=0

We multiply parentheses ..

1x^2+(-1x^2+7x+6x-42)-10=0

We add all the numbers together, and all the variables

x^2+(-1x^2+7x+6x-42)-10=0

We get rid of parentheses

x^2-1x^2+7x+6x-42-10=0

We add all the numbers together, and all the variables

13x-52=0

We move all terms containing x to the left, all other terms to the right

13x=52

x=52/13

x=4

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