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(x-6)(7x+3)=-3
We move all terms to the left:
(x-6)(7x+3)-(-3)=0
We add all the numbers together, and all the variables
(x-6)(7x+3)+3=0
We multiply parentheses ..
(+7x^2+3x-42x-18)+3=0
We get rid of parentheses
7x^2+3x-42x-18+3=0
We add all the numbers together, and all the variables
7x^2-39x-15=0
a = 7; b = -39; c = -15;
Δ = b2-4ac
Δ = -392-4·7·(-15)
Δ = 1941
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-39)-\sqrt{1941}}{2*7}=\frac{39-\sqrt{1941}}{14} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-39)+\sqrt{1941}}{2*7}=\frac{39+\sqrt{1941}}{14} $
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