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(x-6)(x+3)=70
We move all terms to the left:
(x-6)(x+3)-(70)=0
We multiply parentheses ..
(+x^2+3x-6x-18)-70=0
We get rid of parentheses
x^2+3x-6x-18-70=0
We add all the numbers together, and all the variables
x^2-3x-88=0
a = 1; b = -3; c = -88;
Δ = b2-4ac
Δ = -32-4·1·(-88)
Δ = 361
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{361}=19$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-3)-19}{2*1}=\frac{-16}{2} =-8 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-3)+19}{2*1}=\frac{22}{2} =11 $
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