(x-6)(x+6)=(x-2)(x+5)-2

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Solution for (x-6)(x+6)=(x-2)(x+5)-2 equation: 



(x-6)(x+6)=(x-2)(x+5)-2

We move all terms to the left:

(x-6)(x+6)-((x-2)(x+5)-2)=0

We use the square of the difference formula

x^2-((x-2)(x+5)-2)-36=0

We multiply parentheses ..

x^2-((+x^2+5x-2x-10)-2)-36=0



We calculate terms in parentheses: -((+x^2+5x-2x-10)-2), so:

(+x^2+5x-2x-10)-2

We get rid of parentheses

x^2+5x-2x-10-2

We add all the numbers together, and all the variables

x^2+3x-12

Back to the equation:

-(x^2+3x-12)



We get rid of parentheses

x^2-x^2-3x+12-36=0

We add all the numbers together, and all the variables

-3x-24=0

We move all terms containing x to the left, all other terms to the right

-3x=24

x=24/-3

x=-8

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