(x-6)(x-2)=(x-4)(x-5)

Solution for (x-6)(x-2)=(x-4)(x-5) equation:

(x-6)(x-2)=(x-4)(x-5)

We move all terms to the left:

(x-6)(x-2)-((x-4)(x-5))=0

We multiply parentheses ..

(+x^2-2x-6x+12)-((x-4)(x-5))=0


We calculate terms in parentheses: -((x-4)(x-5)), so:

(x-4)(x-5)

We multiply parentheses ..

(+x^2-5x-4x+20)

We get rid of parentheses

x^2-5x-4x+20

We add all the numbers together, and all the variables

x^2-9x+20

Back to the equation:

-(x^2-9x+20)


We get rid of parentheses

x^2-x^2-2x-6x+9x+12-20=0

We add all the numbers together, and all the variables

x-8=0

We move all terms containing x to the left, all other terms to the right

x=8