(x-6)(x-3)-(x-7)(x-7)=24

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Solution for (x-6)(x-3)-(x-7)(x-7)=24 equation: 



(x-6)(x-3)-(x-7)(x-7)=24

We move all terms to the left:

(x-6)(x-3)-(x-7)(x-7)-(24)=0

We multiply parentheses ..

(+x^2-3x-6x+18)-(x-7)(x-7)-24=0

We get rid of parentheses

x^2-3x-6x-(x-7)(x-7)+18-24=0

We multiply parentheses ..

x^2-(+x^2-7x-7x+49)-3x-6x+18-24=0

We add all the numbers together, and all the variables

x^2-(+x^2-7x-7x+49)-9x-6=0

We get rid of parentheses

x^2-x^2+7x+7x-9x-49-6=0

We add all the numbers together, and all the variables

5x-55=0

We move all terms containing x to the left, all other terms to the right

5x=55

x=55/5

x=11

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