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(x-6)(x-4)=24
We move all terms to the left:
(x-6)(x-4)-(24)=0
We multiply parentheses ..
(+x^2-4x-6x+24)-24=0
We get rid of parentheses
x^2-4x-6x+24-24=0
We add all the numbers together, and all the variables
x^2-10x=0
a = 1; b = -10; c = 0;
Δ = b2-4ac
Δ = -102-4·1·0
Δ = 100
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{100}=10$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-10)-10}{2*1}=\frac{0}{2} =0 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-10)+10}{2*1}=\frac{20}{2} =10 $
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