(x-6)(x-7)=(x+3)(x-7)

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Solution for (x-6)(x-7)=(x+3)(x-7) equation:



(x-6)(x-7)=(x+3)(x-7)
We move all terms to the left:
(x-6)(x-7)-((x+3)(x-7))=0
We multiply parentheses ..
(+x^2-7x-6x+42)-((x+3)(x-7))=0
We calculate terms in parentheses: -((x+3)(x-7)), so:
(x+3)(x-7)
We multiply parentheses ..
(+x^2-7x+3x-21)
We get rid of parentheses
x^2-7x+3x-21
We add all the numbers together, and all the variables
x^2-4x-21
Back to the equation:
-(x^2-4x-21)
We get rid of parentheses
x^2-x^2-7x-6x+4x+42+21=0
We add all the numbers together, and all the variables
-9x+63=0
We move all terms containing x to the left, all other terms to the right
-9x=-63
x=-63/-9
x=+7

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