(x-6)*(-12+2*x)=3024

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Solution for (x-6)*(-12+2*x)=3024 equation:



(x-6)(-12+2x)=3024
We move all terms to the left:
(x-6)(-12+2x)-(3024)=0
We add all the numbers together, and all the variables
(x-6)(2x-12)-3024=0
We multiply parentheses ..
(+2x^2-12x-12x+72)-3024=0
We get rid of parentheses
2x^2-12x-12x+72-3024=0
We add all the numbers together, and all the variables
2x^2-24x-2952=0
a = 2; b = -24; c = -2952;
Δ = b2-4ac
Δ = -242-4·2·(-2952)
Δ = 24192
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:
$\sqrt{\Delta}=\sqrt{24192}=\sqrt{576*42}=\sqrt{576}*\sqrt{42}=24\sqrt{42}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-24)-24\sqrt{42}}{2*2}=\frac{24-24\sqrt{42}}{4} $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-24)+24\sqrt{42}}{2*2}=\frac{24+24\sqrt{42}}{4} $

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