(x-6)/(-x-2)=(x+3)/(x-1)

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Solution for (x-6)/(-x-2)=(x+3)/(x-1) equation:


D( x )

-x-2 = 0

x-1 = 0

-x-2 = 0

-x-2 = 0

-x-2 = 0 // + 2

-x = 2 // * -1

x = -2

x-1 = 0

x-1 = 0

x-1 = 0 // + 1

x = 1

x in (-oo:-2) U (-2:1) U (1:+oo)

(x-6)/(-x-2) = (x+3)/(x-1) // - (x+3)/(x-1)

(x-6)/(-x-2)-((x+3)/(x-1)) = 0

(x-6)/(-x-2)+(-1*(x+3))/(x-1) = 0

((x-6)*(x-1))/((-x-2)*(x-1))+(-1*(x+3)*(-x-2))/((-x-2)*(x-1)) = 0

(x-6)*(x-1)-1*(x+3)*(-x-2) = 0

2*x^2-2*x+12 = 0

2*x^2-2*x+12 = 0

2*(x^2-x+6) = 0

x^2-x+6 = 0

DELTA = (-1)^2-(1*4*6)

DELTA = -23

DELTA < 0

2 = 0

2/((-x-2)*(x-1)) = 0

2/((-x-2)*(x-1)) = 0 // * (-x-2)*(x-1)

2 = 0

x belongs to the empty set

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