(x-6)/2=3-(x+6)/9

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Solution for (x-6)/2=3-(x+6)/9 equation: 



(x-6)/2=3-(x+6)/9

We move all terms to the left:

(x-6)/2-(3-(x+6)/9)=0

We calculate fractions


x/()+(-(3-(x+6)*2)/()=0



We calculate terms in parentheses: +(-(3-(x+6)*2)/(), so:

-(3-(x+6)*2)/(

We multiply all the terms by the denominator


-(3-(x+6)*2)



We calculate terms in parentheses: -(3-(x+6)*2), so:

3-(x+6)*2

determiningTheFunctionDomain
-(x+6)*2+3

We multiply parentheses

-2x-12+3

We add all the numbers together, and all the variables

-2x-9

Back to the equation:

-(-2x-9)



We get rid of parentheses

2x+9

Back to the equation:

+(2x+9)



We get rid of parentheses

x/()+2x+9=0

We multiply all the terms by the denominator


x+2x*()+9*()=0

We add all the numbers together, and all the variables

x+2x*()=0

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