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(x-6)=x(x-3)
We move all terms to the left:
(x-6)-(x(x-3))=0
We get rid of parentheses
x-(x(x-3))-6=0
We calculate terms in parentheses: -(x(x-3)), so:We get rid of parentheses
x(x-3)
We multiply parentheses
x^2-3x
Back to the equation:
-(x^2-3x)
-x^2+x+3x-6=0
We add all the numbers together, and all the variables
-1x^2+4x-6=0
a = -1; b = 4; c = -6;
Δ = b2-4ac
Δ = 42-4·(-1)·(-6)
Δ = -8
Delta is less than zero, so there is no solution for the equation
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