(x-6/2)+(6/2)=(x/7)

Solution for (x-6/2)+(6/2)=(x/7) equation:

(x-6/2)+(6/2)=(x/7)

We move all terms to the left:

(x-6/2)+(6/2)-((x/7))=0

We add all the numbers together, and all the variables

(x-3)-((+x/7))+3=0

We get rid of parentheses

x-((+x/7))-3+3=0

We multiply all the terms by the denominator


x*7))-((+x-3*7))+3*7))=0

We add all the numbers together, and all the variables

x*7))-((x-21))+3*7))=0

We add all the numbers together, and all the variables

x*7))-((x=0

Wy multiply elements

7x^2=0

a = 7; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·7·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{14}=0$