(x-6/5x)+1=x+4/x

Solution for (x-6/5x)+1=x+4/x equation:

(x-6/5x)+1=x+4/x

We move all terms to the left:

(x-6/5x)+1-(x+4/x)=0


Domain of the equation: 5x)!=0

x!=0/1

x!=0

x∈R



Domain of the equation: x)!=0

x!=0/1

x!=0

x∈R


We add all the numbers together, and all the variables

(+x-6/5x)-(+x+4/x)+1=0

We get rid of parentheses

x-6/5x-x-4/x+1=0

We calculate fractions


x-x+(-6x)/5x^2+(-20x)/5x^2+1=0

We add all the numbers together, and all the variables

(-6x)/5x^2+(-20x)/5x^2+1=0

We multiply all the terms by the denominator


(-6x)+(-20x)+1*5x^2=0

Wy multiply elements

5x^2+(-6x)+(-20x)=0

We get rid of parentheses

5x^2-6x-20x=0

We add all the numbers together, and all the variables

5x^2-26x=0

a = 5; b = -26; c = 0;
Δ = b2-4ac
Δ = -262-4·5·0
Δ = 676
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{676}=26$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-26)-26}{2*5}=\frac{0}{10}
=0
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-26)+26}{2*5}=\frac{52}{10}
=5+1/5
$