(x-7)(2x+14)=0

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Solution for (x-7)(2x+14)=0 equation:



(x-7)(2x+14)=0
We multiply parentheses ..
(+2x^2+14x-14x-98)=0
We get rid of parentheses
2x^2+14x-14x-98=0
We add all the numbers together, and all the variables
2x^2-98=0
a = 2; b = 0; c = -98;
Δ = b2-4ac
Δ = 02-4·2·(-98)
Δ = 784
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{784}=28$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-28}{2*2}=\frac{-28}{4} =-7 $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+28}{2*2}=\frac{28}{4} =7 $

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