(x-7)(x-7)-(1-x)(1-x)=2(3x-4)

Solution for (x-7)(x-7)-(1-x)(1-x)=2(3x-4) equation:

(x-7)(x-7)-(1-x)(1-x)=2(3x-4)

We move all terms to the left:

(x-7)(x-7)-(1-x)(1-x)-(2(3x-4))=0

We add all the numbers together, and all the variables

(x-7)(x-7)-(-1x+1)(-1x+1)-(2(3x-4))=0

We multiply parentheses ..

(+x^2-7x-7x+49)-(-1x+1)(-1x+1)-(2(3x-4))=0


We calculate terms in parentheses: -(2(3x-4)), so:

2(3x-4)

We multiply parentheses

6x-8

Back to the equation:

-(6x-8)


We get rid of parentheses

x^2-7x-7x-(-1x+1)(-1x+1)-6x+49+8=0

We multiply parentheses ..

x^2-(+x^2-1x-1x+1)-7x-7x-6x+49+8=0

We add all the numbers together, and all the variables

x^2-(+x^2-1x-1x+1)-20x+57=0

We get rid of parentheses

x^2-x^2+1x+1x-20x-1+57=0

We add all the numbers together, and all the variables

-18x+56=0

We move all terms containing x to the left, all other terms to the right

-18x=-56

x=-56/-18

x=3+1/9