(x-7)/3=(x-6)/2

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Solution for (x-7)/3=(x-6)/2 equation: 



(x-7)/3=(x-6)/2

We move all terms to the left:

(x-7)/3-((x-6)/2)=0

We calculate fractions


x/()+(-((x-6)*3)/()=0



We calculate terms in parentheses: +(-((x-6)*3)/(), so:

-((x-6)*3)/(

We multiply all the terms by the denominator


-((x-6)*3)



We calculate terms in parentheses: -((x-6)*3), so:

(x-6)*3

We multiply parentheses

3x-18

Back to the equation:

-(3x-18)



We get rid of parentheses

-3x+18

Back to the equation:

+(-3x+18)



We get rid of parentheses

x/()-3x+18=0

We multiply all the terms by the denominator


x-3x*()+18*()=0

We add all the numbers together, and all the variables

x-3x*()=0

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