(x-7)/6=(x+3)/7

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Solution for (x-7)/6=(x+3)/7 equation:



(x-7)/6=(x+3)/7
We move all terms to the left:
(x-7)/6-((x+3)/7)=0
We calculate fractions
x/()+(-((x+3)*6)/()=0
We calculate terms in parentheses: +(-((x+3)*6)/(), so:
-((x+3)*6)/(
We multiply all the terms by the denominator
-((x+3)*6)
We calculate terms in parentheses: -((x+3)*6), so:
(x+3)*6
We multiply parentheses
6x+18
Back to the equation:
-(6x+18)
We get rid of parentheses
-6x-18
Back to the equation:
+(-6x-18)
We get rid of parentheses
x/()-6x-18=0
We multiply all the terms by the denominator
x-6x*()-18*()=0
We add all the numbers together, and all the variables
x-6x*()=0

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