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(x-7)x=23
We move all terms to the left:
(x-7)x-(23)=0
We multiply parentheses
x^2-7x-23=0
a = 1; b = -7; c = -23;
Δ = b2-4ac
Δ = -72-4·1·(-23)
Δ = 141
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-7)-\sqrt{141}}{2*1}=\frac{7-\sqrt{141}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-7)+\sqrt{141}}{2*1}=\frac{7+\sqrt{141}}{2} $
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