If it's not what You are looking for type in the equation solver your own equation and let us solve it.
(x-8)(3x-4)=1
We move all terms to the left:
(x-8)(3x-4)-(1)=0
We multiply parentheses ..
(+3x^2-4x-24x+32)-1=0
We get rid of parentheses
3x^2-4x-24x+32-1=0
We add all the numbers together, and all the variables
3x^2-28x+31=0
a = 3; b = -28; c = +31;
Δ = b2-4ac
Δ = -282-4·3·31
Δ = 412
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{412}=\sqrt{4*103}=\sqrt{4}*\sqrt{103}=2\sqrt{103}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-28)-2\sqrt{103}}{2*3}=\frac{28-2\sqrt{103}}{6} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-28)+2\sqrt{103}}{2*3}=\frac{28+2\sqrt{103}}{6} $
| 6(2g+2)=3(5g-2) | | 3q-8=-8 | | 85=5(2r+1) | | 2d-12=3d+5-3+1d | | 5n-5=3n+23 | | (3x+2)/5=(4x-7)/6 | | 8j-2=62 | | 8a2-4a=1 | | 4(2t+2)=2(3t+5) | | 7-e=3e-33 | | 15000(1-d)^11=800 | | 5x-35=x*2 | | x*2=(x-9)+(х-17)+(х-5)+(х-3)+(х-1) | | x=((x-9)+(х-17)+(х-5)+(х-3)+(х-1))/2 | | x=((Х-9)+(х-17)+(х-5)+(х-3)+(х-1))/2 | | (x-9)+(x-17)+(x-5)+(x-3)+(x-1)=x*2 | | 0’30/x=18 | | 3x+7=18x+21 | | 0=-16t^2-256 | | 5x+4-2x-9=10 | | 3.65/x=0.2 | | -3(4x+6x)-4(3-1)=43 | | 2x+4+5x=13x+4x | | 2x+4x+5x=13x+4x | | 4(5y02)=52 | | 7x–21–3x+13=7+6x–19 | | 3(x+10)=70 | | 3x−11=7 | | 4k-(k+12)=2k-11 | | 3x+2=5x10 | | x^2-x+2.56=0 | | -3(2x-9)=7/5-6x |