(x-8)(5x+-6)=0

Solution for (x-8)(5x+-6)=0 equation:

(x-8)(5x+-6)=0

We add all the numbers together, and all the variables

(x-8)(5x-6)=0

We multiply parentheses ..

(+5x^2-6x-40x+48)=0

We get rid of parentheses

5x^2-6x-40x+48=0

We add all the numbers together, and all the variables

5x^2-46x+48=0

a = 5; b = -46; c = +48;
Δ = b2-4ac
Δ = -462-4·5·48
Δ = 1156
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1156}=34$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-46)-34}{2*5}=\frac{12}{10}
=1+1/5
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-46)+34}{2*5}=\frac{80}{10}
=8
$