(x-8)(x+2)=(x-6)(x-4)

Solution for (x-8)(x+2)=(x-6)(x-4) equation:

(x-8)(x+2)=(x-6)(x-4)

We move all terms to the left:

(x-8)(x+2)-((x-6)(x-4))=0

We multiply parentheses ..

(+x^2+2x-8x-16)-((x-6)(x-4))=0


We calculate terms in parentheses: -((x-6)(x-4)), so:

(x-6)(x-4)

We multiply parentheses ..

(+x^2-4x-6x+24)

We get rid of parentheses

x^2-4x-6x+24

We add all the numbers together, and all the variables

x^2-10x+24

Back to the equation:

-(x^2-10x+24)


We get rid of parentheses

x^2-x^2+2x-8x+10x-16-24=0

We add all the numbers together, and all the variables

4x-40=0

We move all terms containing x to the left, all other terms to the right

4x=40

x=40/4

x=10