(x-8)(x-8)-(x+3)(x+3)=-15x+97

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Solution for (x-8)(x-8)-(x+3)(x+3)=-15x+97 equation:



(x-8)(x-8)-(x+3)(x+3)=-15x+97
We move all terms to the left:
(x-8)(x-8)-(x+3)(x+3)-(-15x+97)=0
We get rid of parentheses
(x-8)(x-8)-(x+3)(x+3)+15x-97=0
We multiply parentheses ..
(+x^2-8x-8x+64)-(x+3)(x+3)+15x-97=0
We add all the numbers together, and all the variables
(+x^2-8x-8x+64)+15x-(x+3)(x+3)-97=0
We get rid of parentheses
x^2-8x-8x+15x-(x+3)(x+3)+64-97=0
We multiply parentheses ..
x^2-(+x^2+3x+3x+9)-8x-8x+15x+64-97=0
We add all the numbers together, and all the variables
x^2-(+x^2+3x+3x+9)-1x-33=0
We get rid of parentheses
x^2-x^2-3x-3x-1x-9-33=0
We add all the numbers together, and all the variables
-7x-42=0
We move all terms containing x to the left, all other terms to the right
-7x=42
x=42/-7
x=-6

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